ajax 简单的表单验证

<%@ page language="java" contentType="text/html; charset=UTF-8"
    pageEncoding="UTF-8"%>
<!DOCTYPE html>

<html>
		<script type="text/javascript" src="js/jquery-3.3.1.min.js"></script>
		<script type="text/javascript" src="js/jquery-migrate-1.4.1.min.js">
			
		</script> 
	<head>
		<meta charset="UTF-8">
		<title></title>
	</head>
	<form id="form">
		测试<input type="text" onblur="show()" name="ajax" id="ajxa1" value="11" /><span id="test"></span>
		
		
	</form>
	<script>
		function show(){
		/* 	var formData = new FormData(); */
			var ajax1=$("#ajxa1").val();
		
	/* 		formData.append("ajax",ajax1); */
			$.ajax({
				//请求类型
				type:"post",
				//传参的地址(servlet地址)
				url:"test",
				//传整个表单
				/* data:$('#form').serialize(), */
				//传参的数据   
				data:"ajax="+ajax1,
				//返回的值
				success:function(result){
				
					$("#test").text(result)
			
			
					
				}
			}); 
			
		}
	</script>
	
	<body>
	</body>
</html>
package test.servlert;


/**
 * Servlet implementation class test
 */
@WebServlet("/test")
public class test extends HttpServlet {
	


	protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
		// TODO Auto-generated method stub
		//测试前台传过来的值
		System.out.println(request.getParameter("ajax"));
		//传参给前台
		response.getWriter().println("res");
	}